Howard,

So, what is the right way? Could you give me an example how to set this up or give me a reference to a good source on this?

Thank you!

Greetz,

Fred



2012/2/22 Howard Chu <hyc@symas.com>
Fred van Zwieten wrote:
Hi llg,

I fail to see how this solves my RBAC need.

Let me give an example:

Say, personA is in ou DeptA. Then, ideally personA would based on being in
this ou, become member of group webserver

No, when I move personA to ou DeptB, this would mean that, on the next login,
it looses it's membership to group Webserver, but now becomes member of ie
group mailservers

This way, you implement security policies based on the role of a person.

This is not the right way to implement roles. Generally DNs are intended to be constant (though obviously they are allowed to change, changes should be infrequent).

How could this ideally be done with OpenLDAP?

Greetz,

Fred <http://epsilon.eridani.nl>



2012/2/22 llg <llg@portaildulibre.fr <mailto:llg@portaildulibre.fr>>


   Hi,
       persons should use inetOrgPerson and PosixAccount schemas : gidNumber
   gives primary group.

   Then define specific branch ou=posix based on PosixGroup schema and add
   the uid of the person in memberUid multiple values attribute to specify
   secondary gid.

   Regards
   Llg

   Le 22/02/2012 10:22, Fred van Zwieten a écrit :
   Hi all,

   warning: openldap newbie..

   is it possible to have a person put into an OU and, because of this,
   will become member of some group in such a way that this group shows up
   in linux using "id". This to implement some form of RBAC. I found
   GroupofMembers, but that has nothing to do with OU's. Also, it seems
   posixGroup and groupOfMembers objecttypes are no longer allowed together
   because the are both STRUCTURAL.

   In AD this is possible.

   Greetz,

   Fred <http://epsilon.eridani.nl>





--
 -- Howard Chu
 CTO, Symas Corp.           http://www.symas.com
 Director, Highland Sun     http://highlandsun.com/hyc/
 Chief Architect, OpenLDAP  http://www.openldap.org/project/